hce_kmu
109年
物理及化學
第 10 題
An object is placed at a distance 5.0 cm to the left of a concave mirror with a curvature radius 5.0 cm. Determine the location and magnification of the image formed by this image system.
- A The image is formed 2.5 cm to the right of the mirror and it has a magnification of $-1/2$.
- B The image is formed 5.0 cm to the right of the mirror and it has a magnification of $-1$.
- C The image is formed 2.5 cm to the left of the mirror and it has a magnification of $1$.
- D The image is formed 5.0 cm to the left of the mirror and it has a magnification of $-1$.
- E The image is formed 1.25 cm to the left of the mirror and it has a magnification of $-1/4$.
思路引導 VIP
如果我們知道一個球面鏡的曲率半徑是 5 公分，你能先推算出它的「焦距」是多少嗎？接著，當物體剛好放在與曲率半徑等長的距離時，試著回想或畫出兩條特殊光線（例如平行主軸的光線與通過焦點的光線），看看它們最終會在哪個位置交會呢？
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AI 詳解
AI 專屬家教
恭喜你精確地判斷出成像的位置與性質！這題你掌握得非常紮實，展現了對面鏡成像規律的熟練運用。
面鏡成像的特殊位置
在光學中，當物體置於凹面鏡（Concave mirror）的曲率中心時，是一個非常經典的物理情境。題目給定曲率半徑 $R = 5.0$ cm，這意味著焦距 $f = \frac{R}{2} = 2.5$ cm。當物距 $d_o = 5.0$ cm 時，物體恰好位於兩倍焦距處（即曲率中心）。根據面鏡公式：
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